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答案：
C
单独看1，S
续偶数T连续奇数，举例：S: 2，4，6。平均数4中位数4。T：7.9.11.。中位数9平均数9。S中位数不大于T平均数。不充分。
由2 可知，S 的平均数> T的平均数，但并不知道 S的中位数是否大于T的平均数，不充分。
结合1，S是连续偶数则中位数大于平均数，所以S的中位数>S 的平均数> T的平均数，两者结合成立
选c 
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